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123456789#include <stdio.h> int main() { int num = 3; if (num) printf("True"); if (num == 0) printf("False"); return 0; }

Question

123456789#include <stdio.h> int main() { int num = 3; if (num) printf("True"); if (num == 0) printf("False"); return 0; }

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Solution

The code you've written is in C language. It's a simple program that checks if a number is zero or not. Here's a step-by-step explanation:

  1. #include <stdio.h>: This is a preprocessor command that includes the standard input-output library in the program.

  2. int main(): This is the main function where the program execution begins.

  3. int num = 3;: Here, an integer type variable num is declared and initialized with the value 3.

  4. if (num) printf("True");: This is an if statement that checks if num is not zero. If num is not zero, it prints "True". Since num is 3, it will print "True".

  5. if (num == 0) printf("False");: This is another if statement that checks if num is zero. If num is zero, it prints "False". Since num is 3, it will not print anything.

  6. return 0;: This statement ends the main function and returns the value 0.

So, when you run this program, it will print "True" because num is not zero.

This problem has been solved

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