Select the correct answerA train passes a stationary pole in 8 seconds.The train also passes a 200 m long bridge in 28 seconds. What is the length and the speed of the train?OptionsLength = 70m; Speed = 20 m/sLength = 50m; Speed = 10 m/sLength = 90m; Speed = 40 m/sLength = 80m; Speed = 10 m/s
Question
Select the correct answerA train passes a stationary pole in 8 seconds.The train also passes a 200 m long bridge in 28 seconds. What is the length and the speed of the train?OptionsLength = 70m; Speed = 20 m/sLength = 50m; Speed = 10 m/sLength = 90m; Speed = 40 m/sLength = 80m; Speed = 10 m/s
Solution
To solve this problem, we need to understand that when a train passes a stationary object like a pole, the distance it covers is equal to the length of the train.
Step 1: The train passes a pole in 8 seconds. So, the length of the train is equal to the distance covered in these 8 seconds. Let's denote the speed of the train as 'v'. So, the length of the train (L) can be calculated as:
L = v * time L = v * 8 seconds
Step 2: The train also passes a 200m long bridge in 28 seconds. When a train passes a bridge, the distance it covers is equal to the length of the train plus the length of the bridge. So, we can write:
L + 200m = v * 28 seconds
Step 3: We can solve these two equations to find the values of L (length of the train) and v (speed of the train).
From the first equation, we get v = L / 8.
Substitute v in the second equation, we get:
L + 200m = (L / 8) * 28 L + 200m = 3.5L 200m = 2.5L L = 200m / 2.5 = 80m
Substitute L = 80m in the first equation, we get:
v = 80m / 8 seconds = 10 m/s
So, the length of the train is 80m and the speed is 10 m/s.
Therefore, the correct answer is "Length = 80m; Speed = 10 m/s".
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