Given an integer x, return true if x is a palindrome, and false otherwise. Example 1:Input: x = 121Output: trueExplanation: 121 reads as 121 from left to right and from right to left.Example 2:Input: x = -121Output: falseExplanation: From left to right, it reads -121. From right to left, it becomes 121-. Therefore it is not a palindrome.Example 3:Input: x = 10Output: falseExplanation: Reads 01 from right to left. Therefore it is not a palindrome.
Question
Given an integer x, return true if x is a palindrome, and false otherwise. Example 1:Input: x = 121Output: trueExplanation: 121 reads as 121 from left to right and from right to left.Example 2:Input: x = -121Output: falseExplanation: From left to right, it reads -121. From right to left, it becomes 121-. Therefore it is not a palindrome.Example 3:Input: x = 10Output: falseExplanation: Reads 01 from right to left. Therefore it is not a palindrome.
Solution
Sure, here is a Python solution for the problem:
def isPalindrome(x):
if x < 0:
return False
else:
return str(x) == str(x)[::-1]
This function works as follows:
- If
xis less than 0, it immediately returnsFalsebecause negative numbers are not palindromes (as per the problem statement). - If
xis not negative, it convertsxto a string and checks if this string is the same when read backwards (which is whatstr(x)[::-1]does). If it is, it returnsTrue; otherwise, it returnsFalse.
For example, if you call isPalindrome(121), it will return True. If you call isPalindrome(-121) or isPalindrome(10), it will return False.
Similar Questions
Given an integer x, return true if x is a palindrome, and false otherwise.
class Solution { public boolean isPalindrome(int x) { String num =Integer.toString(x); for(int i=num.length()-1;i<0;i--){ String a =" "+num; if(num==a){ System.out.println("it is palindrome:"+a); }else{ System.out.println("it is not palindrome:"+a); } } }}
A phrase is a palindrome if, after converting all uppercase letters into lowercase letters and removing all non-alphanumeric characters, it reads the same forward and backward. Alphanumeric characters include letters and numbers.Given a string s, return true if it is a palindrome, or false otherwise. Example 1:Input: s = "A man, a plan, a canal: Panama"Output: trueExplanation: "amanaplanacanalpanama" is a palindrome.Example 2:Input: s = "race a car"Output: falseExplanation: "raceacar" is not a palindrome.Example 3:Input: s = " "Output: trueExplanation: s is an empty string "" after removing non-alphanumeric characters.Since an empty string reads the same forward and backward, it is a palindrome. Constraints:1 <= s.length <= 2 * 105s consists only of printable ASCII characters.
Write a C++ program to check if a given number is a palindrome. A palindrome is a number that remains the same when its digits are reversed.
Problem StatementSusi loves playing with numbers and exploring their unique properties. One day, she learned about palindromic numbers and decided to write a program to check if a given number is a palindrome or not. Can you help her accomplish this task using a while loop?Note: palindrome is a number that is the same when reversed. For example, 121, 1331, and 45654 are palindromic numbers.Input format :The input consists of a single integer, n, where n is the number that Susi wants to check for palindromic properties.Output format :The output displays one of the following messages:"Palindrome" if n is a palindrome."Not a Palindrome" if n is not a palindrome.Refer to the sample output for the formatting specifications.Code constraints :In this scenario, the test cases fall under the following constraints:11 ≤ n ≤ 106Sample test cases :Input 1 :2552Output 1 :PalindromeInput 2 :1234Output 2 :Not a PalindromeInput 3 :11Output 3 :PalindromeInput 4 :1000000Output 4 :Not a Palindrome
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