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If 2xy+3yx=20, then dydx at (2,2) is equal to:

Question

If 2xy+3yx=20, then dydx at (2,2) is equal to:

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Solution

The given equation is 2xy + 3yx = 20.

First, we simplify the equation. Since xy and yx are the same, we can combine like terms:

2xy + 3xy = 20 5xy = 20

Next, we solve for y:

y = 20 / (5x) y = 4 / x

Now, we find the derivative of y with respect to x (dy/dx):

dy/dx = -4 / x^2

Finally, we substitute x = 2 into the derivative to find the value of dy/dx at (2,2):

dy/dx = -4 / (2^2) dy/dx = -4 / 4 dy/dx = -1

So, dy/dx at (2,2) is -1.

This problem has been solved

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