The postfix form of P*Q+R/S is?Options*PQ/RS+PQRS+/*P*QR+/SPQ*RS/+
Question
The postfix form of PQ+R/S is?OptionsPQ/RS+PQRS+/PQR+/SPQ*RS/+
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Solution
The postfix form of PQ+R/S is PQRS/+.
Here's the step-by-step conversion from infix to postfix:
- Scan the infix expression from left to right.
- If the scanned character is an operand, output it.
- Else,
- If the precedence of the scanned operator is greater than the precedence of the operator in the stack(or the stack is empty), push it.
- Else, Pop the operator from the stack until the precedence of the scanned operator is less-equal to the precedence of the operator residing on the top of the stack. Push the scanned operator to the stack.
- If the scanned character is an '(', push it to the stack.
- If the scanned character is an ')', pop and output from the stack until an '(' is encountered.
- Repeat steps 2-6 until infix expression is scanned.
- Pop and output from the stack until it is not empty.
So, for the expression P*Q+R/S:
- Scan P, it's an operand, so output it. (Output: P)
- Scan *, it's an operator, push it to the stack. (Stack: *)
- Scan Q, it's an operand, so output it. (Output: PQ)
- Scan , it's an operator, pop * from the stack and output it, then push * to the stack. (Output: PQ, Stack: *)
- Scan +, it's an operator, push it to the stack. (Stack: +*)
- Scan R, it's an operand, so output it. (Output: PQ*R)
- Scan /, it's an operator, push it to the stack. (Stack: /*+)
- Scan S, it's an operand, so output it. (Output: PQ*R/S)
- Scan +, it's an operator, pop / from the stack and output it, then push + to the stack. (Output: PQ*RS/+, Stack: +)
So, the postfix form of PQ+R/S is PQRS/+.
Similar Questions
Select the correct answerThe postfix form of P*Q+R/S is?OptionsP*QR+/SPQ*RS/+*PQ/RS+PQRS+/*
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The postfix form of A*B+C/D is?Options*AB/CD+ABCD+/*A*BC+/SAB*CD/+
postfix form
The postfix form of A*B+C/D is?
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