The problem seems to be a bit confusing, but I'll try to break it down as best as I can.

Step 1: Find out how much coal one engine consumes in one hour.
We know that 9 engines consume 24 metric tons of coal in 8 hours. So, one engine would consume 24/9 = 2.67 metric tons of coal in 8 hours. Therefore, in one hour, one engine consumes 2.67/8 = 0.33 metric tons of coal.

Step 2: Find out how much coal 8 engines consume in 13 hours.
If one engine consumes 0.33 metric tons of coal in one hour, then 8 engines would consume 8 * 0.33 = 2.67 metric tons of coal in one hour. Therefore, in 13 hours, 8 engines would consume 2.67 * 13 = 34.71 metric tons of coal.

Step 3: Adjust for the difference in engine types.
It's given that 3 engines of the first type consume as much as 4 engines of the second type. This means that the second type of engine consumes 3/4 as much coal as the first type. Therefore, 8 engines of the second type would consume 34.71 * (3/4) = 26.03 metric tons of coal in 13 hours.

So, 8 engines of the second type running for 13 hours a day would require approximately 26.03 metric tons of coal.

Question

The problem seems to be a bit confusing, but I'll try to break it down as best as I can.

Step 1: Find out how much coal one engine consumes in one hour.
We know that 9 engines consume 24 metric tons of coal in 8 hours. So, one engine would consume 24/9 = 2.67 metric tons of coal in 8 hours. Therefore, in one hour, one engine consumes 2.67/8 = 0.33 metric tons of coal.

Step 2: Find out how much coal 8 engines consume in 13 hours.
If one engine consumes 0.33 metric tons of coal in one hour, then 8 engines would consume 8 * 0.33 = 2.67 metric tons of coal in one hour. Therefore, in 13 hours, 8 engines would consume 2.67 * 13 = 34.71 metric tons of coal.

Step 3: Adjust for the difference in engine types.
It's given that 3 engines of the first type consume as much as 4 engines of the second type. This means that the second type of engine consumes 3/4 as much coal as the first type. Therefore, 8 engines of the second type would consume 34.71 * (3/4) = 26.03 metric tons of coal in 13 hours.

So, 8 engines of the second type running for 13 hours a day would require approximately 26.03 metric tons of coal.

Knowee AI · Accepted Answer

The problem seems to be a bit confusing, but I'll try to break it down as best as I can.

Step 1: Find out how much coal one engine consumes in one hour.
We know that 9 engines consume 24 metric tons of coal in 8 hours. So, one engine would consume 24/9 = 2.67 metric tons of coal in 8 hours. Therefore, in one hour, one engine consumes 2.67/8 = 0.33 metric tons of coal.

Step 2: Find out how much coal 8 engines consume in 13 hours.
If one engine consumes 0.33 metric tons of coal in one hour, then 8 engines would consume 8 * 0.33 = 2.67 metric tons of coal in one hour. Therefore, in 13 hours, 8 engines would consume 2.67 * 13 = 34.71 metric tons of coal.

Step 3: Adjust for the difference in engine types.
It's given that 3 engines of the first type consume as much as 4 engines of the second type. This means that the second type of engine consumes 3/4 as much coal as the first type. Therefore, 8 engines of the second type would consume 34.71 * (3/4) = 26.03 metric tons of coal in 13 hours.

So, 8 engines of the second type running for 13 hours a day would require approximately 26.03 metric tons of coal.

1If 9 engines consume 24 metric of coal , when each is working a 8 hours a day ;how much coal will required for 8 engines each running 13 hours a day it is been given that 3 engines of former type consume 4 engines of latter type ?

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